[原创]MD5计算器
文章作者：赛冰河 [E.S.T]信息来源：邪恶八进制信息安全团队（[url]www.eviloctal.com[/url]）
前几天看到论坛有人在说32与16的关系，好多网站只取16位只是为了方便，
今晚查了下资料，把32的MD5与16位的搞清楚了，16是只是截取了32位的中间部分
如果需要源代码（VC）：请联系
截图如下：
[img]http://blog.csdn.net/images/blog_csdn_net/amh/a.bmp.jpg[/img] 呵呵，赛冰河，我很喜欢你 编写的这个 MD5计算器 的软件，能给我发一份源代码吗？
我会 好好学习研究的，谢谢您！！ ^_^ 偶的 信箱： [email]xyz24k@sina.com[/email] [quote][b]下面是引用赛冰河于2005-05-03 13:59发表的[原创]MD5计算器:[/b]
今晚查了下资料，把32的MD5与16位的搞清楚了，16是只是截取了32位的中间部分[/quote]
我记得好像以前有个帖子，我早有在里面说16位是截取了32位的中间部分，结果我后面有人跟帖说不是的，只要转换一下加密方式，就不是这样了！最后好像也没什么人说明到底是怎么样 我用你的计算器算的结果和老兵之前写那个MD5计算器的结果不大一样阿
现在在学校机房没有老兵的那个计算器,
回到宿舍我再发截图上来 冰河兄的MD5计算器的确有问题，加密一些符号的时候计算出来的是错误的值。
比如加密 $ 出来的结果：
32：16a27f78e766afb3632faae062280b4a
16：e766afb3632faae0
我用我的EST-EvilHsu计算出来是：
32：c3e97dd6e97fb5125688c97f36720cbe
16：e97fb5125688c97f
再用其他朋友写的来测试证明我的结果是正确的。 还有，不知道为什么冰河写的软件这么大？加了壳还这么大？难道是软件皮肤？还不如自己找点资料用API画呢 风泽的是应该是正确的.....
[quote]
C:\Program Files\MySQL\MySQL Server 5.0\bin>mysql -uroot -p -hlocalhost
Enter password: ****
Welcome to the MySQL monitor. Commands end with ; or \g.
Your MySQL connection id is 1 to server version: 5.0.12-beta-nt
Type 'help;' or '\h' for help. Type '\c' to clear the buffer.
mysql> select md5('$')
-> ;
+----------------------------------+
| md5('$') |
+----------------------------------+
| c3e97dd6e97fb5125688c97f36720cbe |
+----------------------------------+
1 row in set (0.09 sec)
mysql>
[/quote]
32: c3e97dd6e97fb5125688c97f36720cbe
16: e97fb5125688c97f
冰河的,应该是那几个基数改改过了一下吧.不晓得了 [quote][b]下面是引用狙击鹰于2005-09-22 11:03发表的:[/b]
我用你的计算器算的结果和老兵之前写那个MD5计算器的结果不大一样阿
现在在学校机房没有老兵的那个计算器,
回到宿舍我再发截图上来[/quote]
不给我发图上来的阿
自己找个地方去.......
[img]http://www.xyx-tattoo.com/bbs/images/123.jpg[/img] 应该不是基数改了，我估计他对要加密的值操作有错误。
[attach]431[/attach]
第一次加密MD5这个值是错误的，以后都是正确的。
加密很不稳定。我又加密了一次 $ 结果和上次又不一样了。
[attach]432[/attach] 用js就可以完成,如果放在网站上,使用起来会更方面些,我手头上有代码 t1D92nxf4TQ2aaurQI3BBA
今天遇到这种MD5密码，不是16位也不是32位，但确实存在，是邮箱加密后的密码 那是MD5么，会不会象serv-u密码那样 [quote][b]下面是引用史翔于2005-09-27 13:57发表的:[/b]
那是MD5么，会不会象serv-u密码那样[/quote]
不是serv-u密码，是eyou邮箱的密码，从excel表里看到的，前面有{md5} 后面有==
中间就是密码了，难道没人知道这是怎么加密的吗？ [quote][b]下面是引用chinaren于2005-09-27 13:42发表的:[/b]
t1D92nxf4TQ2aaurQI3BBA
今天遇到这种MD5密码，不是16位也不是32位，但确实存在，是邮箱加密后的密码[/quote]
读代码咯
貌似DVBBS的TRUEPASSWORD也是这个样子的 16位的md5java怎么写木有想出来 [quote][b]下面是引用chinaren于2005-09-27 13:42发表的:[/b]
t1D92nxf4TQ2aaurQI3BBA
今天遇到这种MD5密码，不是16位也不是32位，但确实存在，是邮箱加密后的密码[/quote]
邮箱密码是用base64加密后提交的啊~ [quote][b]下面是引用风泽于2005-09-28 21:10发表的:[/b]
邮箱密码是用base64加密后提交的啊~[/quote]
base64加密的可以还原吗？ DLL的源代码：Base64Dll.asm
;***********************************************
;程序名称：演示Base64编码/解码原理
;作者：罗聪
;日期：2002-9-14
;出处：[url]http://laoluoc.yeah.net[/url]（老罗的缤纷天地）
;注意事项：如欲转载，请保持本程序的完整，并注明：
;转载自“老罗的缤纷天地”（[url]http://laoluoc.yeah.net[/url]）
;***********************************************
.386
.model flat, stdcall
option casemap:none
include \masm32\include\windows.inc
include \masm32\include\kernel32.inc
include \masm32\include\user32.inc
includelib \masm32\lib\kernel32.lib
includelib \masm32\lib\user32.lib
DllEntry proto :HINSTANCE, :DWORD, :DWORD
Base64Encode proto :DWORD, :DWORD
Base64Decode proto :DWORD, :DWORD
.data
;Base64 -> ASCII mapping table
base64_alphabet db "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/="
;ASCII -> Base64 mapping table
base64table db 43 dup (255)
db 62,255,255,255,63,52,53,54,55,56,57,58,59,60,61,255
db 255,255,0,255,255,255,0,1,2,3,4,5,6,7,8,9,10,11,12,13
db 14,15,16,17,18,19,20,21,22,23,24,25,255,255,255,255
db 255,255,26,27,28,29,30,31,32,33,34,35,36,37,38
db 39,40,41,42,43,44,45,46,47,48,49,50,51
db 132 dup (255)
.code
DllEntry proc hInst: HINSTANCE, reason: DWORD, reserved1: DWORD
mov eax, TRUE
ret
DllEntry endp
;**********************************************************
;函数功能：进行Base64编码
;参数：
; source = 传入的字符串
; destination = 返回的编码
;**********************************************************
Base64Encode proc uses ebx edi esi source:DWORD, destination:DWORD
LOCAL sourcelen:DWORD
invoke lstrlen, source
mov sourcelen, eax
mov esi, source
mov edi, destination
@@base64loop:
xor eax, eax
.if sourcelen == 1
lodsb ;source ptr + 1
mov ecx, 2 ;bytes to output = 2
mov edx, 03D3Dh ;padding = 2 byte
dec sourcelen ;length - 1
.elseif sourcelen == 2
lodsw ;source ptr + 2
mov ecx, 3 ;bytes to output = 3
mov edx, 03Dh ;padding = 1 byte
sub sourcelen, 2 ;length - 2
.else
lodsd
mov ecx, 4 ;bytes to output = 4
xor edx, edx ;padding = 0 byte
dec esi ;source ptr + 3 (+4-1)
sub sourcelen, 3 ;length - 3
.endif
xchg al,ah ;flip eax completely
rol eax, 16 ;can this be done faster
xchg al,ah
@@:
push eax
and eax, 0FC000000h ;get the last 6 high bits
rol eax, 6 ;rotate them into al
mov al, byte ptr [offset base64_alphabet + eax] ;get encode character
stosb ;write to destination
pop eax
shl eax, 6 ;shift left 6 bits
dec ecx
jnz @B ;loop
cmp sourcelen, 0
jnz @@base64loop ;main loop
mov eax, edx ;add padding and null terminate
stosd
ret
Base64Encode endp
;**********************************************************
;函数功能：进行Base64解码
;参数：
; source = 传入的编码
; destination = 返回的字符串
;**********************************************************
Base64Decode proc uses ebx edi esi source:DWORD, destination:DWORD
LOCAL sourcelen:DWORD
invoke lstrlen, source
mov sourcelen, eax
mov esi, source ;esi <- source
mov edi, destination ;edi <- destination
mov ecx, sourcelen
shr ecx, 2
cld
;-------------[decoding part]---------------
@@outer_loop:
push ecx
mov ecx, 4
xor ebx, ebx
lodsd
@@inner_loop:
push eax
and eax, 0ffh
mov al, byte ptr [offset base64table + eax]
cmp al, 255
je @@invalid_char
shl ebx, 6
or bl, al
pop eax
shr eax, 8
dec ecx
jnz @@inner_loop
mov eax, ebx
shl eax, 8
xchg ah, al
ror eax, 16
xchg ah, al
stosd
dec edi
pop ecx
dec ecx
jnz @@outer_loop
xor eax, eax
jmp @@decode_done
;-------------------------------------------
@@invalid_char:
mov eax, -1
@@decode_done:
ret
Base64Decode ENDP
end DllEntry
;******************** over ********************
;by LC
-------------------------------------------------------------------------------- ASP的
base64解密
<%
sBASE_64_CHARACTERS = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/"
sBASE_64_CHARACTERS = strUnicode2Ansi(sBASE_64_CHARACTERS)
Function strUnicodeLen(asContents)
'计算unicode字符串的Ansi编码的长度
asContents1="a"&asContents
len1=len(asContents1)
k=0
for i=1 to len1
asc1=asc(mid(asContents1,i,1))
if asc1<0 then asc1=65536+asc1
if asc1>255 then
k=k+2
else
k=k+1
end if
next
strUnicodeLen=k-1
End Function
Function strUnicode2Ansi(asContents)
'将Unicode编码的字符串，转换成Ansi编码的字符串
strUnicode2Ansi=""
len1=len(asContents)
for i=1 to len1
varchar=mid(asContents,i,1)
varasc=asc(varchar)
if varasc<0 then varasc=varasc+65536
if varasc>255 then
varHex=Hex(varasc)
varlow=left(varHex,2)
varhigh=right(varHex,2)
strUnicode2Ansi=strUnicode2Ansi & chrb("&H" & varlow ) & chrb("&H" & varhigh )
else
strUnicode2Ansi=strUnicode2Ansi & chrb(varasc)
end if
next
End function
Function strAnsi2Unicode(asContents)
'将Ansi编码的字符串，转换成Unicode编码的字符串
strAnsi2Unicode = ""
len1=lenb(asContents)
if len1=0 then exit function
for i=1 to len1
varchar=midb(asContents,i,1)
varasc=ascb(varchar)
if varasc > 127 then
strAnsi2Unicode = strAnsi2Unicode & chr(ascw(midb(asContents,i+1,1) & varchar))
i=i+1
else
strAnsi2Unicode = strAnsi2Unicode & chr(varasc)
end if
next
End function
Function Base64encode(asContents)
'将Ansi编码的字符串进行Base64编码
'asContents应当是ANSI编码的字符串（二进制的字符串也可以）
Dim lnPosition
Dim lsResult
Dim Char1
Dim Char2
Dim Char3
Dim Char4
Dim Byte1
Dim Byte2
Dim Byte3
Dim SaveBits1
Dim SaveBits2
Dim lsGroupBinary
Dim lsGroup64
Dim m4,len1,len2
len1=Lenb(asContents)
if len1<1 then
Base64encode=""
exit Function
end if
m3=Len1 Mod 3
If M3 > 0 Then asContents = asContents & String(3-M3, chrb(0))
'补足位数是为了便于计算
IF m3 > 0 THEN
len1=len1+(3-m3)
len2=len1-3
else
len2=len1
end if
lsResult = ""
For lnPosition = 1 To len2 Step 3
lsGroup64 = ""
lsGroupBinary = Midb(asContents, lnPosition, 3)
Byte1 = Ascb(Midb(lsGroupBinary, 1, 1)): SaveBits1 = Byte1 And 3
Byte2 = Ascb(Midb(lsGroupBinary, 2, 1)): SaveBits2 = Byte2 And 15
Byte3 = Ascb(Midb(lsGroupBinary, 3, 1))
Char1 = Midb(sBASE_64_CHARACTERS, ((Byte1 And 252) \ 4) + 1, 1)
Char2 = Midb(sBASE_64_CHARACTERS, (((Byte2 And 240) \ 16) Or (SaveBits1 * 16) And &HFF) + 1, 1)
Char3 = Midb(sBASE_64_CHARACTERS, (((Byte3 And 192) \ 64) Or (SaveBits2 * 4) And &HFF) + 1, 1)
Char4 = Midb(sBASE_64_CHARACTERS, (Byte3 And 63) + 1, 1)
lsGroup64 = Char1 & Char2 & Char3 & Char4
lsResult = lsResult & lsGroup64
Next
'处理最后剩余的几个字符
if M3 > 0 then
lsGroup64 = ""
lsGroupBinary = Midb(asContents, len2+1, 3)
Byte1 = Ascb(Midb(lsGroupBinary, 1, 1)): SaveBits1 = Byte1 And 3
Byte2 = Ascb(Midb(lsGroupBinary, 2, 1)): SaveBits2 = Byte2 And 15
Byte3 = Ascb(Midb(lsGroupBinary, 3, 1))
Char1 = Midb(sBASE_64_CHARACTERS, ((Byte1 And 252) \ 4) + 1, 1)
Char2 = Midb(sBASE_64_CHARACTERS, (((Byte2 And 240) \ 16) Or (SaveBits1 * 16) And &HFF) + 1, 1)
Char3 = Midb(sBASE_64_CHARACTERS, (((Byte3 And 192) \ 64) Or (SaveBits2 * 4) And &HFF) + 1, 1)
if M3=1 then
lsGroup64 = Char1 & Char2 & ChrB(61) & ChrB(61) '用=号补足位数
else
lsGroup64 = Char1 & Char2 & Char3 & ChrB(61) '用=号补足位数
end if
lsResult = lsResult & lsGroup64
end if
Base64encode = lsResult
End Function
Function Base64decode(asContents)
'将Base64编码字符串转换成Ansi编码的字符串
'asContents应当也是ANSI编码的字符串（二进制的字符串也可以）
Dim lsResult
Dim lnPosition
Dim lsGroup64, lsGroupBinary
Dim Char1, Char2, Char3, Char4
Dim Byte1, Byte2, Byte3
Dim M4,len1,len2
len1= Lenb(asContents)
M4 = len1 Mod 4
if len1 < 1 or M4 > 0 then
'字符串长度应当是4的倍数
Base64decode = ""
exit Function
end if
'判断最后一位是不是 = 号
'判断倒数第二位是不是 = 号
'这里m4表示最后剩余的需要单独处理的字符个数
if midb(asContents, len1, 1) = chrb(61) then m4=3
if midb(asContents, len1-1, 1) = chrb(61) then m4=2
if m4 = 0 then
len2=len1
else
len2=len1-4
end if
For lnPosition = 1 To Len2 Step 4
lsGroupBinary = ""
lsGroup64 = Midb(asContents, lnPosition, 4)
Char1 = InStrb(sBASE_64_CHARACTERS, Midb(lsGroup64, 1, 1)) - 1
Char2 = InStrb(sBASE_64_CHARACTERS, Midb(lsGroup64, 2, 1)) - 1
Char3 = InStrb(sBASE_64_CHARACTERS, Midb(lsGroup64, 3, 1)) - 1
Char4 = InStrb(sBASE_64_CHARACTERS, Midb(lsGroup64, 4, 1)) - 1
Byte1 = Chrb(((Char2 And 48) \ 16) Or (Char1 * 4) And &HFF)
Byte2 = lsGroupBinary & Chrb(((Char3 And 60) \ 4) Or (Char2 * 16) And &HFF)
Byte3 = Chrb((((Char3 And 3) * 64) And &HFF) Or (Char4 And 63))
lsGroupBinary = Byte1 & Byte2 & Byte3
lsResult = lsResult & lsGroupBinary
Next
'处理最后剩余的几个字符
if M4 > 0 then
lsGroupBinary = ""
lsGroup64 = Midb(asContents, len2+1, m4) & chrB(65) 'chr(65)=A，转换成值为0
if M4=2 then '补足4位，是为了便于计算
lsGroup64 = lsGroup64 & chrB(65)
end if
Char1 = InStrb(sBASE_64_CHARACTERS, Midb(lsGroup64, 1, 1)) - 1
Char2 = InStrb(sBASE_64_CHARACTERS, Midb(lsGroup64, 2, 1)) - 1
Char3 = InStrb(sBASE_64_CHARACTERS, Midb(lsGroup64, 3, 1)) - 1
Char4 = InStrb(sBASE_64_CHARACTERS, Midb(lsGroup64, 4, 1)) - 1
Byte1 = Chrb(((Char2 And 48) \ 16) Or (Char1 * 4) And &HFF)
Byte2 = lsGroupBinary & Chrb(((Char3 And 60) \ 4) Or (Char2 * 16) And &HFF)
Byte3 = Chrb((((Char3 And 3) * 64) And &HFF) Or (Char4 And 63))
if M4=2 then
lsGroupBinary = Byte1
elseif M4=3 then
lsGroupBinary = Byte1 & Byte2
end if
lsResult = lsResult & lsGroupBinary
end if
Base64decode = lsResult
End Function
sdecode="aHR0cDovL3d3dy5sYW1raW5nLmNvbS90ZXN0Lzg4c2FkZmc3ODg3OS5hc3A="
response.write replace(strAnsi2Unicode(Base64decode(strUnicode2Ansi(sdecode))),chr(13)&chr(10),"<br>") & "<hr>"
response.end
%> 看的头都晕了，能解密吗....................................................,复制一大堆代码能解决实际问题吗 倒了,你自己弄个IIS,把ASP代码挂上,不就可以了 郁闷MD532转MDB516转换,就是取掉32的前8位,取掉后8位,就是32位到16的转换,单方面的转换. <INPUT class=fmbtn id=test value=史翔>
<INPUT class=fmbtn type=button value=加密 onclick="sx.value=calcMD5(test.value)">
<INPUT class=fmbtn id=sx value="这里显示md5的密码">
<script>
/* to convert strings to a list of ascii values */
var sAscii = " !\"#$%&'()*+,-./0123456789:;<=>?@ABCDEFGHIJKLMNOPQRSTUVWXYZ"
var sAscii = sAscii + "[\\]^_`abcdefghijklmnopqrstuvwxyz{|}~";
/* convert integer to hex string */
var sHex = "0123456789ABCDEF";
function hex(i)
{
h = "";
for(j = 0; j <= 3; j++)
{
h += sHex.charAt((i >> (j * 8 + 4)) & 0x0F) +
sHex.charAt((i >> (j * 8)) & 0x0F);
}
return h;
}
/* add, handling overflows correctly */
function add(x, y)
{
return ((x&0x7FFFFFFF) + (y&0x7FFFFFFF)) ^ (x&0x80000000) ^ (y&0x80000000);
}
/* MD5 rounds functions */
function R1(A, B, C, D, X, S, T)
{
q = add(add(A, (B & C) | (~B & D)), add(X, T));
return add((q << S) | ((q >> (32 - S)) & (Math.pow(2, S) - 1)), B);
}
function R2(A, B, C, D, X, S, T)
{
q = add(add(A, (B & D) | (C & ~D)), add(X, T));
return add((q << S) | ((q >> (32 - S)) & (Math.pow(2, S) - 1)), B);
}
function R3(A, B, C, D, X, S, T)
{
q = add(add(A, B ^ C ^ D), add(X, T));
return add((q << S) | ((q >> (32 - S)) & (Math.pow(2, S) - 1)), B);
}
function R4(A, B, C, D, X, S, T)
{
q = add(add(A, C ^ (B | ~D)), add(X, T));
return add((q << S) | ((q >> (32 - S)) & (Math.pow(2, S) - 1)), B);
}
/* main entry point */
function calcMD5(sInp) {
/* Calculate length in machine words, including padding */
wLen = (((sInp.length + 8) >> 6) + 1) << 4;
var X = new Array(wLen);
/* Convert string to array of words */
j = 4;
for (i = 0; (i * 4) < sInp.length; i++)
{
X[i] = 0;
for (j = 0; (j < 4) && ((j + i * 4) < sInp.length); j++)
{
X[i] += (sAscii.indexOf(sInp.charAt((i * 4) + j)) + 32) << (j * 8);
}
}
/* Append padding bits and length */
if (j == 4)
{
X[i++] = 0x80;
}
else
{
X[i - 1] += 0x80 << (j * 8);
}
for(; i < wLen; i++) { X[i] = 0; }
X[wLen - 2] = sInp.length * 8;
/* hard-coded initial values */
a = 0x67452301;
b = 0xefcdab89;
c = 0x98badcfe;
d = 0x10325476;
/* Process each 16-word block in turn */
for (i = 0; i < wLen; i += 16) {
aO = a;
bO = b;
cO = c;
dO = d;
a = R1(a, b, c, d, X[i+ 0], 7 , 0xd76aa478);
d = R1(d, a, b, c, X[i+ 1], 12, 0xe8c7b756);
c = R1(c, d, a, b, X[i+ 2], 17, 0x242070db);
b = R1(b, c, d, a, X[i+ 3], 22, 0xc1bdceee);
a = R1(a, b, c, d, X[i+ 4], 7 , 0xf57c0faf);
d = R1(d, a, b, c, X[i+ 5], 12, 0x4787c62a);
c = R1(c, d, a, b, X[i+ 6], 17, 0xa8304613);
b = R1(b, c, d, a, X[i+ 7], 22, 0xfd469501);
a = R1(a, b, c, d, X[i+ 8], 7 , 0x698098d8);
d = R1(d, a, b, c, X[i+ 9], 12, 0x8b44f7af);
c = R1(c, d, a, b, X[i+10], 17, 0xffff5bb1);
b = R1(b, c, d, a, X[i+11], 22, 0x895cd7be);
a = R1(a, b, c, d, X[i+12], 7 , 0x6b901122);
d = R1(d, a, b, c, X[i+13], 12, 0xfd987193);
c = R1(c, d, a, b, X[i+14], 17, 0xa679438e);
b = R1(b, c, d, a, X[i+15], 22, 0x49b40821);
a = R2(a, b, c, d, X[i+ 1], 5 , 0xf61e2562);
d = R2(d, a, b, c, X[i+ 6], 9 , 0xc040b340);
c = R2(c, d, a, b, X[i+11], 14, 0x265e5a51);
b = R2(b, c, d, a, X[i+ 0], 20, 0xe9b6c7aa);
a = R2(a, b, c, d, X[i+ 5], 5 , 0xd62f105d);
d = R2(d, a, b, c, X[i+10], 9 , 0x2441453);
c = R2(c, d, a, b, X[i+15], 14, 0xd8a1e681);
b = R2(b, c, d, a, X[i+ 4], 20, 0xe7d3fbc8);
a = R2(a, b, c, d, X[i+ 9], 5 , 0x21e1cde6);
d = R2(d, a, b, c, X[i+14], 9 , 0xc33707d6);
c = R2(c, d, a, b, X[i+ 3], 14, 0xf4d50d87);
b = R2(b, c, d, a, X[i+ 8], 20, 0x455a14ed);
a = R2(a, b, c, d, X[i+13], 5 , 0xa9e3e905);
d = R2(d, a, b, c, X[i+ 2], 9 , 0xfcefa3f8);
c = R2(c, d, a, b, X[i+ 7], 14, 0x676f02d9);
b = R2(b, c, d, a, X[i+12], 20, 0x8d2a4c8a);
a = R3(a, b, c, d, X[i+ 5], 4 , 0xfffa3942);
d = R3(d, a, b, c, X[i+ 8], 11, 0x8771f681);
c = R3(c, d, a, b, X[i+11], 16, 0x6d9d6122);
b = R3(b, c, d, a, X[i+14], 23, 0xfde5380c);
a = R3(a, b, c, d, X[i+ 1], 4 , 0xa4beea44);
d = R3(d, a, b, c, X[i+ 4], 11, 0x4bdecfa9);
c = R3(c, d, a, b, X[i+ 7], 16, 0xf6bb4b60);
b = R3(b, c, d, a, X[i+10], 23, 0xbebfbc70);
a = R3(a, b, c, d, X[i+13], 4 , 0x289b7ec6);
d = R3(d, a, b, c, X[i+ 0], 11, 0xeaa127fa);
c = R3(c, d, a, b, X[i+ 3], 16, 0xd4ef3085);
b = R3(b, c, d, a, X[i+ 6], 23, 0x4881d05);
a = R3(a, b, c, d, X[i+ 9], 4 , 0xd9d4d039);
d = R3(d, a, b, c, X[i+12], 11, 0xe6db99e5);
c = R3(c, d, a, b, X[i+15], 16, 0x1fa27cf8);
b = R3(b, c, d, a, X[i+ 2], 23, 0xc4ac5665);
a = R4(a, b, c, d, X[i+ 0], 6 , 0xf4292244);
d = R4(d, a, b, c, X[i+ 7], 10, 0x432aff97);
c = R4(c, d, a, b, X[i+14], 15, 0xab9423a7);
b = R4(b, c, d, a, X[i+ 5], 21, 0xfc93a039);
a = R4(a, b, c, d, X[i+12], 6 , 0x655b59c3);
d = R4(d, a, b, c, X[i+ 3], 10, 0x8f0ccc92);
c = R4(c, d, a, b, X[i+10], 15, 0xffeff47d);
b = R4(b, c, d, a, X[i+ 1], 21, 0x85845dd1);
a = R4(a, b, c, d, X[i+ 8], 6 , 0x6fa87e4f);
d = R4(d, a, b, c, X[i+15], 10, 0xfe2ce6e0);
c = R4(c, d, a, b, X[i+ 6], 15, 0xa3014314);
b = R4(b, c, d, a, X[i+13], 21, 0x4e0811a1);
a = R4(a, b, c, d, X[i+ 4], 6 , 0xf7537e82);
d = R4(d, a, b, c, X[i+11], 10, 0xbd3af235);
c = R4(c, d, a, b, X[i+ 2], 15, 0x2ad7d2bb);
b = R4(b, c, d, a, X[i+ 9], 21, 0xeb86d391);
a = add(a, aO);
b = add(b, bO);
c = add(c, cO);
d = add(d, dO);
}
return hex(b) + hex(c);
}
</script> <INPUT class=fmbtn id=test value=史翔>
<INPUT class=fmbtn type=button value=加密 onclick="sx.value=hex_md5(test.value)">
<INPUT class=fmbtn id=sx value="这里显示md5的密码">
<script>
var hexcase = 0; /* hex output format. 0 - lowercase; 1 - uppercase
*/
var b64pad = ""; /* base-64 pad character. "=" for strict RFC
compliance */
var chrsz = 8; /* bits per input character. 8 - ASCII; 16 - Unicode
*/
/*
* These are the functions you'll usually want to call
* They take string arguments and return either hex or base-64 encoded
strings
*/
function hex_md5(s){ return binl2hex(core_md5(str2binl(s), s.length *
chrsz));}
function b64_md5(s){ return binl2b64(core_md5(str2binl(s), s.length *
chrsz));}
function hex_hmac_md5(key, data) { return binl2hex(core_hmac_md5(key,
data)); }
function b64_hmac_md5(key, data) { return binl2b64(core_hmac_md5(key,
data)); }
/* Backwards compatibility - same as hex_md5() */
function calcMD5(s){ return binl2hex(core_md5(str2binl(s), s.length *
chrsz));}
/*
* Perform a simple self-test to see if the VM is working
*/
function md5_vm_test()
{
return hex_md5("abc") == "900150983cd24fb0d6963f7d28e17f72";
}
/*
* Calculate the MD5 of an array of little-endian words, and a bit
length
*/
function core_md5(x, len)
{
/* append padding */
x[len >> 5] |= 0x80 << ((len) % 32);
x[(((len + 64) >>> 9) << 4) + 14] = len;
var a = 1732584193;
var b = -271733879;
var c = -1732584194;
var d = 271733878;
for(var i = 0; i < x.length; i += 16)
{
var olda = a;
var oldb = b;
var oldc = c;
var oldd = d;
a = md5_ff(a, b, c, d, x[i+ 0], 7 , -680876936);
d = md5_ff(d, a, b, c, x[i+ 1], 12, -389564586);
c = md5_ff(c, d, a, b, x[i+ 2], 17, 606105819);
b = md5_ff(b, c, d, a, x[i+ 3], 22, -1044525330);
a = md5_ff(a, b, c, d, x[i+ 4], 7 , -176418897);
d = md5_ff(d, a, b, c, x[i+ 5], 12, 1200080426);
c = md5_ff(c, d, a, b, x[i+ 6], 17, -1473231341);
b = md5_ff(b, c, d, a, x[i+ 7], 22, -45705983);
a = md5_ff(a, b, c, d, x[i+ 8], 7 , 1770035416);
d = md5_ff(d, a, b, c, x[i+ 9], 12, -1958414417);
c = md5_ff(c, d, a, b, x[i+10], 17, -42063);
b = md5_ff(b, c, d, a, x[i+11], 22, -1990404162);
a = md5_ff(a, b, c, d, x[i+12], 7 , 1804603682);
d = md5_ff(d, a, b, c, x[i+13], 12, -40341101);
c = md5_ff(c, d, a, b, x[i+14], 17, -1502002290);
b = md5_ff(b, c, d, a, x[i+15], 22, 1236535329);
a = md5_gg(a, b, c, d, x[i+ 1], 5 , -165796510);
d = md5_gg(d, a, b, c, x[i+ 6], 9 , -1069501632);
c = md5_gg(c, d, a, b, x[i+11], 14, 643717713);
b = md5_gg(b, c, d, a, x[i+ 0], 20, -373897302);
a = md5_gg(a, b, c, d, x[i+ 5], 5 , -701558691);
d = md5_gg(d, a, b, c, x[i+10], 9 , 38016083);
c = md5_gg(c, d, a, b, x[i+15], 14, -660478335);
b = md5_gg(b, c, d, a, x[i+ 4], 20, -405537848);
a = md5_gg(a, b, c, d, x[i+ 9], 5 , 568446438);
d = md5_gg(d, a, b, c, x[i+14], 9 , -1019803690);
c = md5_gg(c, d, a, b, x[i+ 3], 14, -187363961);
b = md5_gg(b, c, d, a, x[i+ 8], 20, 1163531501);
a = md5_gg(a, b, c, d, x[i+13], 5 , -1444681467);
d = md5_gg(d, a, b, c, x[i+ 2], 9 , -51403784);
c = md5_gg(c, d, a, b, x[i+ 7], 14, 1735328473);
b = md5_gg(b, c, d, a, x[i+12], 20, -1926607734);
a = md5_hh(a, b, c, d, x[i+ 5], 4 , -378558);
d = md5_hh(d, a, b, c, x[i+ 8], 11, -2022574463);
c = md5_hh(c, d, a, b, x[i+11], 16, 1839030562);
b = md5_hh(b, c, d, a, x[i+14], 23, -35309556);
a = md5_hh(a, b, c, d, x[i+ 1], 4 , -1530992060);
d = md5_hh(d, a, b, c, x[i+ 4], 11, 1272893353);
c = md5_hh(c, d, a, b, x[i+ 7], 16, -155497632);
b = md5_hh(b, c, d, a, x[i+10], 23, -1094730640);
a = md5_hh(a, b, c, d, x[i+13], 4 , 681279174);
d = md5_hh(d, a, b, c, x[i+ 0], 11, -358537222);
c = md5_hh(c, d, a, b, x[i+ 3], 16, -722521979);
b = md5_hh(b, c, d, a, x[i+ 6], 23, 76029189);
a = md5_hh(a, b, c, d, x[i+ 9], 4 , -640364487);
d = md5_hh(d, a, b, c, x[i+12], 11, -421815835);
c = md5_hh(c, d, a, b, x[i+15], 16, 530742520);
b = md5_hh(b, c, d, a, x[i+ 2], 23, -995338651);
a = md5_ii(a, b, c, d, x[i+ 0], 6 , -198630844);
d = md5_ii(d, a, b, c, x[i+ 7], 10, 1126891415);
c = md5_ii(c, d, a, b, x[i+14], 15, -1416354905);
b = md5_ii(b, c, d, a, x[i+ 5], 21, -57434055);
a = md5_ii(a, b, c, d, x[i+12], 6 , 1700485571);
d = md5_ii(d, a, b, c, x[i+ 3], 10, -1894986606);
c = md5_ii(c, d, a, b, x[i+10], 15, -1051523);
b = md5_ii(b, c, d, a, x[i+ 1], 21, -2054922799);
a = md5_ii(a, b, c, d, x[i+ 8], 6 , 1873313359);
d = md5_ii(d, a, b, c, x[i+15], 10, -30611744);
c = md5_ii(c, d, a, b, x[i+ 6], 15, -1560198380);
b = md5_ii(b, c, d, a, x[i+13], 21, 1309151649);
a = md5_ii(a, b, c, d, x[i+ 4], 6 , -145523070);
d = md5_ii(d, a, b, c, x[i+11], 10, -1120210379);
c = md5_ii(c, d, a, b, x[i+ 2], 15, 718787259);
b = md5_ii(b, c, d, a, x[i+ 9], 21, -343485551);
a = safe_add(a, olda);
b = safe_add(b, oldb);
c = safe_add(c, oldc);
d = safe_add(d, oldd);
}
return Array(a, b, c, d);
}
/*
* These functions implement the four basic operations the algorithm
uses.
*/
function md5_cmn(q, a, b, x, s, t)
{
return safe_add(bit_rol(safe_add(safe_add(a, q), safe_add(x, t)),
s),b);
}
function md5_ff(a, b, c, d, x, s, t)
{
return md5_cmn((b & c) | ((~b) & d), a, b, x, s, t);
}
function md5_gg(a, b, c, d, x, s, t)
{
return md5_cmn((b & d) | (c & (~d)), a, b, x, s, t);
}
function md5_hh(a, b, c, d, x, s, t)
{
return md5_cmn(b ^ c ^ d, a, b, x, s, t);
}
function md5_ii(a, b, c, d, x, s, t)
{
return md5_cmn(c ^ (b | (~d)), a, b, x, s, t);
}
/*
* Calculate the HMAC-MD5, of a key and some data
*/
function core_hmac_md5(key, data)
{
var bkey = str2binl(key);
if(bkey.length > 16) bkey = core_md5(bkey, key.length * chrsz);
var ipad = Array(16), opad = Array(16);
for(var i = 0; i < 16; i++)
{
ipad[i] = bkey[i] ^ 0x36363636;
opad[i] = bkey[i] ^ 0x5C5C5C5C;
}
var hash = core_md5(ipad.concat(str2binl(data)), 512 + data.length *
chrsz);
return core_md5(opad.concat(hash), 512 + 128);
}
/*
* Add integers, wrapping at 2^32. This uses 16-bit operations
internally
* to work around bugs in some JS interpreters.
*/
function safe_add(x, y)
{
var lsw = (x & 0xFFFF) + (y & 0xFFFF);
var msw = (x >> 16) + (y >> 16) + (lsw >> 16);
return (msw << 16) | (lsw & 0xFFFF);
}
/*
* Bitwise rotate a 32-bit number to the left.
*/
function bit_rol(num, cnt)
{
return (num << cnt) | (num >>> (32 - cnt));
}
/*
* Convert a string to an array of little-endian words
* If chrsz is ASCII, characters >255 have their hi-byte silently
ignored.
*/
function str2binl(str)
{
var bin = Array();
var mask = (1 << chrsz) - 1;
for(var i = 0; i < str.length * chrsz; i += chrsz)
bin[i>>5] |= (str.charCodeAt(i / chrsz) & mask) << (i%32);
return bin;
}
/*
* Convert an array of little-endian words to a hex string.
*/
function binl2hex(binarray)
{
var hex_tab = hexcase ? "0123456789ABCDEF" : "0123456789abcdef";
var str = "";
for(var i = 0; i < binarray.length * 4; i++)
{
str += hex_tab.charAt((binarray[i>>2] >> ((i%4)*8+4)) & 0xF) +
hex_tab.charAt((binarray[i>>2] >> ((i%4)*8 )) & 0xF);
}
return str;
}
/*
* Convert an array of little-endian words to a base-64 string
*/
function binl2b64(binarray)
{
var tab =
"ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/";
var str = "";
for(var i = 0; i < binarray.length * 4; i += 3)
{
var triplet = (((binarray[i >> 2] >> 8 * ( i %4)) & 0xFF) <<
16)
| (((binarray[i+1 >> 2] >> 8 * ((i+1)%4)) & 0xFF) << 8
)
| ((binarray[i+2 >> 2] >> 8 * ((i+2)%4)) & 0xFF);
for(var j = 0; j < 4; j++)
{
if(i * 8 + j * 6 > binarray.length * 32) str += b64pad;
else str += tab.charAt((triplet >> 6*(3-j)) & 0x3F);
}
}
return str;
}
</script>
前面是md6 16位ㄉ，后面是md5 32 位
关键是那return hex(b) + hex(c); 应该不难写的，MD5的VBS代码几乎每个ASP程序里面都有！
用VB来写我觉得应该很简单的！
这是Neeao的MD5的截图。
[img]http://www.lucidwood.com/uploads/img43451a30e92d4.jpg[/img] 32位去前8后8就是16位，肯定是。
那前8位和后8位是怎么来的呢？ md5算法几乎全语言的都有,其文沒必要再写一个,因为几乎每个人手上都会有....
php,java等甚致內置了md5
js,vbs,asp,vb,delphi等也有算法
汇编也有,始终都出了很多年.. 在我的笔记本电脑上的破解成绩(512M内存，p4 2.2G)：
98fffa5e1b3bd16c -> 74556788
破出用了61087毫秒...
d27df17b98fffa5e1b3bd16c2e2c68ae -> 74556788
破出用了61088毫秒...
选择最小位1，最大位8位，纯数字破解。 [url]http://www.md5lookup.com/?category=01-3&search=on[/url]
这个地方关于md5还是不错的， EST-EvilHsu有base64解密功能。
下载地址：[url]http://www.eviloctal.com/forum/read.php?tid=16135&fpage=1[/url] 今天遇到一个30位和27位的MD5码,怎样破解呢 [quote][b]这里是引用第[/b][color=#ff0000][15 楼][/color][b]的[color=#000066]风泽[/color]于[/b]2005-09-28 21:10[b]发表的：[/b]
邮箱密码是用base64加密后提交的啊~[/quote]
很多黑客小游戏都有这个的.....呵呵 .... 华夏的那个黑客游戏就有一个有关于此的...... [quote][b]这里是引用第[/b][color=#ff0000][31 楼][/color][b]的[color=#000066]luhao1212[/color]于[/b]2006-06-27 16:27[b]发表的：[/b]
今天遇到一个30位和27位的MD5码,怎样破解呢[/quote]
这位大哥,,,,你还是先去EST新手版块充电吧......偶活了这么久还没见过30位和27位的MD5码......难道是偶要去充电了??????????
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